Development Length

Compute rebar tension development length, Class A/B tension lap splices, and compression development length per ACI 318-19 §25.4 in SI units, with the (cb+Ktr)/db <= 2.5 cap and all modification factors.


ACI 318-19 §25.4

Tension Lap Splice Class

Bar & Materials (SI: MPa, mm)

mm
MPa
MPa

Results

1.00
ψt·ψe (≤ 1.7)
0.8
Size factor ψs
1.00
Grade factor ψg
2.50
(cb+Ktr)/db (≤ 2.5)
369mm
ld general (Eq. 25.4.2.4a)
605mm
ld simplified (Table 25.4.2.3)
369mm
Class A lap (1.0 ld)
480mm
Class B lap (1.3 ld)
305mm
Compression ldc
Governing tension development length ld = 369 mm; selected Class B lap splice = 480 mm.

About Development Length Calculator (ACI 318-19)

The development length calculator computes the embedment length required to develop the yield strength of a deformed reinforcing bar in tension, the corresponding tension lap-splice length, and the compression development length, following ACI 318-19 §25.4. All inputs and outputs use SI units (MPa for strengths, mm for geometry).

It evaluates both the general equation (25.4.2.4a) with the confinement term (cb + Ktr)/db capped at 2.5 and the simplified Table 25.4.2.3 expressions, and applies the modification factors for bar location (psi_t), epoxy coating (psi_e), bar size (psi_s), bar grade (psi_g), and lightweight concrete (lambda). Tension lap splices are reported for Class A (1.0 ld) and Class B (1.3 ld), and compression development uses §25.4.9.

How It Works

  1. Select the tension lap-splice class (A = 1.0 ld, B = 1.3 ld) for the splice you are detailing.
  2. Enter the bar diameter db (mm), yield strength fy (MPa), concrete strength fc (MPa), and the confinement term (cb + Ktr)/db (the code caps it at 2.5).
  3. Toggle the conditions that set the modification factors: top bar (psi_t = 1.3), epoxy coating (psi_e = 1.5, with psi_t*psi_e capped at 1.7), and lightweight concrete (lambda = 0.75).
  4. The calculator returns the general and simplified tension development lengths (with the 300 mm minimum), the Class A and Class B lap splices, and the compression development length ldc (with the 200 mm minimum).

Worked Example

A 16 mm bottom bar (uncoated, normalweight) is developed in fc = 28 MPa concrete with fy = 420 MPa and a confinement term (cb + Ktr)/db = 2.5. The factors are psi_t = 1.0, psi_e = 1.0, psi_s = 0.8 (db <= 19 mm), psi_g = 1.0, and lambda = 1.0. The general equation gives ld = (420*1.0*1.0*0.8*1.0 / (1.1*1.0*sqrt(28)*2.5)) * 16 = (336/14.552)*16 = 369 mm, while the simplified equation gives (420 / (2.1*1.0*sqrt(28))) * 16 = 605 mm. The Class B lap splice is 1.3 * 369 = 480 mm, and the compression development length is ldc = max(0.24*420/sqrt(28), 0.043*420) * 16 = max(19.05, 18.06) * 16 = 305 mm.

Formulas

Tension development length, general (Eq. 25.4.2.4a, SI)
ld = ( fy*psi_t*psi_e*psi_s*psi_g / (1.1*lambda*sqrt(fc)*((cb+Ktr)/db)) ) * db, with (cb+Ktr)/db <= 2.5
Modification factors (Table 25.4.2.5)
psi_t = 1.3 top / 1.0 other ; psi_e = 1.5 epoxy / 1.0 ; psi_s = 0.8 (db<=19mm) / 1.0 ; psi_g = 1.0 / 1.15 / 1.3 ; psi_t*psi_e <= 1.7
Tension development length, simplified (Table 25.4.2.3, SI)
db <= 19 mm: ld = (fy*psi_t*psi_e / (2.1*lambda*sqrt(fc)))*db ; db >= 22 mm: divisor 1.7
Lap splice and compression development
lap: Class A = 1.0 ld, Class B = 1.3 ld ; ldc = max(0.24*fy/(lambda*sqrt(fc)), 0.043*fy)*db >= 200 mm

Standards & References

  • ACI 318-19 Building Code Requirements for Structural Concrete
  • ACI 318-19 §25.4 (development and splices of reinforcement)

Frequently Asked Questions

What is the confinement term (cb + Ktr)/db?

It captures how well the bar is confined by cover and transverse reinforcement. cb is the smaller of the side cover and half the clear bar spacing, and Ktr is the transverse reinforcement index. ACI 318-19 caps (cb + Ktr)/db at 2.5; larger confinement does not further shorten the development length.

When is a Class B lap splice required?

ACI 318-19 §25.5.2 requires a Class B tension lap (1.3 ld) unless the area of reinforcement provided is at least twice that required over the splice length and no more than half the bars are spliced within the lap length, in which case Class A (1.0 ld) may be used.

Why does the general equation give a shorter length than the simplified one here?

The general equation includes the bar-size factor psi_s = 0.8 for small bars and the full confinement term up to 2.5, both of which reduce the length. The simplified equations are conservative shortcuts that omit psi_s and assume a fixed confinement, so they typically return longer lengths.

Does this tool cover hooked or headed bars?

No. It computes straight-bar tension and compression development and straight-bar lap splices. Standard hooks (§25.4.3) and headed bars (§25.4.4) use different equations with their own modification factors and are not included here.